Re: [xsl] Problem with ampersands

Subject: Re: [xsl] Problem with ampersands
From: Jeff Sese <jsese@xxxxxxxxxxxx>
Date: Wed, 27 Sep 2006 10:06:22 +0800
andrew welch wrote:
If you really must deliver XML with the entities in place I would
suggest using a placeholder element (eg <entityA/>) to represent it in
the output and the post process the result with a suitable language to
replace the placeholder elements with the entity references.
This would probably the best way to go with this problem. However how do i go about replacing all the occurrences of the entity equivalent with an element? Is this method the right approach?

<xsl:function name="f:replace-all">
<xsl:param name="input" as="xs:string"/>
<xsl:param name="words-to-replace" as="xs:string*"/>
<xsl:param name="replacement" as="xs:string*"/>
<xsl:sequence select="if (exists($words-to-replace)) then f:replace-all(replace($input, $words-to-replace[1], $replacement[1]),remove($words-to-replace,1),remove($replacement,1)) else $input"/>
</xsl:function>
<xsl:output method="xml" encoding="UTF-8" use-character-maps="brillMaps"/>
<xsl:template match="/">
<xsl:variable name="str" select="'&#x0386; &amp; test test the quick brown fox text&#x0063;&#x0332;&#x0068;&#x0332;&#x006B;&#x0332;text test test the quick brown fox'"/>
<xsl:variable name="replacementStr" as="xs:string*" select="$entityTable/search[matches($str,.)]/following-sibling::replace/concat('&#x3c;entity name=&#x22;',.,'&#x22;/&#x3e;')"/>
<test>
<xsl:value-of select="f:replace-all($str,$entityTable/search[matches($str,.)],$replacementStr)"/>
</test>
</xsl:template>


Wherein, i have a character map with this values:

<xsl:output-character string="&#x3c;" character="&#x3c;"/>
<xsl:output-character string="&#x3e;" character="&#x3e;"/>

Thanks,
-- Jeff

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