Re: [xsl] Get Document File name
Subject: Re: [xsl] Get Document File name|
From: Abel Braaksma <abel.online@xxxxxxxxx>
Date: Mon, 23 Oct 2006 08:35:32 +0200
Frank Marent wrote:
Is there a way to get the file name of the document you are
processing? If I
use Document-uri() it returns the whole file path.
or '\' if working with backslashes.
A backslash cannot be a literal part of a URI, it is not allowed. It
must be escaped for that purpose as %5C. Because a URI may well have
additional information after the 'filename', namely the query part and
the fragment part, I recommend using the regular expression that is
provided as a convenience in the RFC2396 paper. It puts the path in $5::
12 3 4 5 6 7 8 9
You can use the tokenize function above for splitting $5. Not however
that that a path separator not necessarily be a slash, it depends on the
scheme part ($2) what is and what is not allowed in the path expression.
-- Abel Braaksma