Re: [xsl] Getting ordering info from a lookup table

Subject: Re: [xsl] Getting ordering info from a lookup table
From: "Spencer Tickner" <spencertickner@xxxxxxxxx>
Date: Mon, 30 Oct 2006 15:45:49 -0800
Hi, Hope this is what you're looking for

Previous : <xsl:value-of
select="document('temp.xml')/file/doc[following-sibling::doc =
$myself]"/>


Next : <xsl:value-of select="document('temp.xml')/file/doc[preceding-sibling::doc = $myself]"/>


Cheers,


Spencer


On 10/30/06, Trevor Nicholls <trevor@xxxxxxxxxxxxxxxxxx> wrote:
Hello

My transform is using an external XML file as a lookup table. Among other
things, the external file contains a list:
  ...
  <files>
    <doc>file_one</doc>
    <doc>file_two></doc>
    <doc>file_three</doc>
    ...
  </files>

Each time the transform runs, the input XML file corresponds to one of the
<doc> elements in the lookup file. The input file name is passed in as a
parameter to the transformation.

<xsl:param name="myself" />

I think the following construction can do the lookup to the external file
and locate the current doc:

.. select="document('lookup.xml')/files/doc[. = $myself]"

but of course this is pointless by itself as I already have the doc name.
What I actually want is to obtain the names of the previous and next docs -
if they exist. There's surely an elegant way to do this, but I don't know
it. What can I do?

Thanks
Trevor

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