Subject: Re: [xsl] i18n and l10n question From: Nicolas Van Cleemput <nicolas.vancleemput@xxxxxxxx> Date: Thu, 09 Nov 2006 10:39:59 +0100 |
Hmm, I feel stupid: it wasn't working because of a typo I copy/pasted severeal times.
Now there appears text, but it always just returns the first <entry key="parameter.description">descr</entry>. It should only look for the entry-tag inside the current parameter-tag. How do I obtain this result?
Thanks in advance, Nico
OK, now I'm coming to the next step. These factoryfiles also contain a list of
parameters:
<factory> <i18n> ... (this works already ;)) </i18n> <parameter> <name></name> <type></type> <i18n> <properties> <entry key="parameter.description">descr</entry> </properties> <node name="nl"> <properties> <entry key="parameter.description">descr</entry> </properties> </node> </i18n> </parameter> <parameter> <name></name> <type></type> <i18n> <properties> <entry key="parameter.description">descr</entry> </properties> <node name="nl"> <properties> <entry key="parameter.description">descr</entry> </properties> </node> </i18n> </parameter> ...
Now I want to make a table which contains an overview of the parameters. I therefore need to access several of these entry-elements (I only typed the description one for simplicity). Analogue to the previous method I did this:
<xsl:for-each select="parameter">
<tr>
<td>
<xsl:choose>
<xsl:when test="key('l',concat($locale,' parameter.description'))">
<xsl:apply-templates select="key('l',concat($locale,' parameter.description'))"/>
</xsl:when>
<xsl:when test="key('l',concat($locale2,' parameter.description'))">
<xsl:apply-templates select="key('l',concat($locale2,' parameter.description'))"/>
</xsl:when>
<xsl:otherwise>
<xsl:apply-templates select="key('l',' parameter.description')"/>
</xsl:otherwise>
</xsl:choose>
</td>
</tr>
</xsl:for-each>
This finds the correct number of parameters, but nothing is placed inside the table cells. It is as if the entry-elements aren't found.
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