Re: [xsl] generate-id() problem

["Nima Kaviani" <nkaviani@xxxxxx>]

Hi Florent,

thanks for the msg. However your used syntax ( <rule:foo
rdf:ID="rule_{ generate-id(.) }">) is not working for me. My xalan
XSLT Processor complains about the use of  curly braces in the string.
So I have to use it this way: <rule:foo rdf:ID="concat('rule_',
generate-id(.))">

ok I guess at this point it doesn't really matter. I just mentioned it
to check whether this is a problem at the level of the processor or
something else.

thanks for the idea you gave to me. It helps to generate unique ids.

-Nima

On 11/24/06, Florent Georges <darkman_spam@xxxxxxxx> wrote:
> Nima Kaviani wrote:
>
>   Hi
>
> > <rule:foo rdf:ID="rule_N2320">
> >     <rule:bar rdf:resource="constraint_N3456"/>
> > </rule:foo>
>
> > <constraint:test rdf:ID="constraint_N3456">
> >    <t1/>
> >    <t2/>
> > <constraint:tes>
>
> > ok so as it is obvious in the code above, I need to
> > generate two unique values, here "N2320" and "N3456",
> > using a funciton and attach them to my terms, "rule" and
> > "constraint".
>
>   So you can use generate-id() iff you can make a link
> between these generated elements and nodes in your input
> tree.  For example, say that those elements are generated in
> the template for the element "myelem", that have a mandatory
> attribute "myattr".  Then you can write:
>
>     <xsl:template match="myelem">
>       <!-- Will always generate the same string for the same
>            myelem node in the same transformation. -->
>       <rule:foo rdf:ID="rule_{ generate-id(.) }">
>         ...
>       </rule:foo>
>       <!-- Will always generate the same string for the same
>            @myattr node in the same transformation. -->
>       <constraint:test
>           rdf:ID="constraint_{ generate-id(@myattr) }">
>         ..
>       <constraint:tes>
>     </xsl:template>
>
>   Regards,
>
> --drkm
>
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