Subject: [xsl] new bie question From: chun ji <cji_work@xxxxxxxxx> Date: Mon, 4 Dec 2006 15:26:57 -0800 (PST) |
I have an index.xml file, which reads as: " -<?xml version="1.0" encoding="ISO-8859-1" ?> -<?xml-stylesheet href="rules.xsl" type="text/xsl"?> -<protest> -<package> -<name>billing</name> -</package> -<package> -<name>timecard</name> -</package> -</protest> . There is a group of child xml files that associated with each /protest/package/name, such as "billing.xml", "timecard.xml". Now I have soming in my XSL file that tries to open all these CHILD xml files, <xsl:for-each select="document(document('index.xml')/protest/package/name)"> </xsl:for-each> which fails, because I did not give .xml for each child xml. Does someone know the format to do it ? thanks a lot cji ____________________________________________________________________________________ Yahoo! Music Unlimited Access over 1 million songs. http://music.yahoo.com/unlimited
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