Re: [xsl] new bie question

["Spencer Tickner" <spencertickner@xxxxxxxxx>]

Try

concat(document('index.xml')/protest/package/name, '.xml')

Spencer

On 12/4/06, chun ji <cji_work@xxxxxxxxx> wrote:
> I have an index.xml file, which reads as:
> "
> -<?xml version="1.0" encoding="ISO-8859-1" ?>
> -<?xml-stylesheet href="rules.xsl" type="text/xsl"?>
> -<protest>
>     -<package>
>            -<name>billing</name>
>       -</package>
>      -<package>
>            -<name>timecard</name>
>       -</package>
> -</protest>
> ".
> There is a group of child xml files that associated
> with each "/protest/package/name", such as
> "billing.xml", "timecard.xml".
>
> Now I have soming in my XSL file that tries to open
> all these CHILD xml files,
> "
> <xsl:for-each
> select="document(document('index.xml')/protest/package/name)">
> 
> </xsl:for-each>
> "
> which fails, because I did not give ".xml" for each
> child xml.
>
> Does someone know the format to do it ?
>
>
> thanks a lot
>
>
> cji
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