Re: [xsl] XSL FO Table formatting

Subject: Re: [xsl] XSL FO Table formatting
From: "CyberSpace Industries 2000 Inc." <csi2000@xxxxxxxxxxxxxxx>
Date: Wed, 13 Dec 2006 11:46:45 -0500
The reason you get what you do is that there is nothing in your xml to denote what a "row" is.. and nothing in your xslt to denote that either.

I believe that <xsl:for-each select="//DscA | //DscB">
will iterate over the 9 nodes selected and output a single cell in a single row for each.


Are you able to add the intelligence for "row" to your input XML?

Cheers...Hugh
CyberSpace Industries 2000 Inc.
XML Training and Consulting

----- Original Message ----- From: "Dave Dran" <davedran@xxxxxxxxx>
To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
Sent: Wednesday, December 13, 2006 11:18 AM
Subject: [xsl] XSL FO Table formatting



XSL FO Table formatting

--------------------------------------------------------------------------------

Hi!

Help, I think there is a simple solution for this. Can't seem to
format this correctly

Thanks alot.

Dave

<fo:table width="100%">
<fo:table-column column-width="proportional-column-width(50)"/>
<fo:table-column column-width="proportional-column-width(25)"/>
<fo:table-column column-width="proportional-column-width(25)"/>
<fo:table-body>
<xsl:for-each select="//DscA | //DscB">
<fo:table-row line-height="13pt">
<fo:table-cell border-width="1pt" border-style="solid">
<fo:block>
<xsl:value-of select="."/>
</fo:block>
</fo:table-cell>
</fo:table-row>
</xsl:for-each>
</fo:table-body>
</fo:table>

Actual XML Data
<DscA>1. Money</DscA>
<DscA>3,000.00</DscA>
<DscA>0.00</DscA>
<DscA>2. Money</DscA>
<DscB>3,000.00</DscB>
<DscB>0.00</DscB>
<DscB>3. Others</DscB>
<DscB>10,000.00</DscB>
<DscB>0.00</DscB>

The expected output (3 columns)

1. Money 3,000.00 0.00
2. Money 3,000.00 0.00
3. Others 10,000.00 0.00

The current output

1. Money
3,000.00
0.00
2. Money
3,000.00
0.00
3. Others
10,000.00
0.00
TOTAL

Current Thread