Subject: Re: [xsl] Dynamic numbering of lists in xslt From: cknell@xxxxxxxxxx Date: Mon, 08 Jan 2007 14:50:13 -0500 |
That response reminded me of one of my favorite lawyer jokes. Without seeing your XSLT, we can only give you a very general answer. Given what I see in your source code, and assuming that you have a template that matches the "section" element, I would use this: <xsl:template match="section"> <xslt:value-of select="position()" />.<xslt:value-of select="." /> </xslt:template> -- Charles Knell cknell@xxxxxxxxxx - email -----Original Message----- From: xslt.new <xslt.new@xxxxxxxxx> Sent: Mon, 8 Jan 2007 13:20:41 -0600 To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: Re: [xsl] Dynamic numbering of lists in xslt Hi: Thank you for your reply. Can you give me an idea of how this can be achieved? On 1/8/07, Alexey Nickolaenkov <nikolaenkov@xxxxxxxxxxxx> wrote: > yes. > > Monday, January 8, 2007, 10:04:47 PM, you wrote: > > xn> Hi: > > xn> I am a newbie to xslt and XSLFO. I have to do a numbering which offers the > xn> flexibility to reorder elements if an element in between is being removed. > > xn> I will try to demonstrate with an example input. > > xn> <chapter1> > xn> <section>first section<section> > xn> </chapter1> > xn> <chapter1> > xn> <section>second section</section> > xn> </chapter1> > xn> <chapter1> > xn> <section>third section</section> > xn> </chapter1> > xn> <chapter1> > xn> <section>fourth section</section> > xn> </chapter1> > > xn> So, I want my output to look like > > xn> 1. first section > xn> 2. second section > xn> 3. third section > xn> 4. fourth section > > xn> and so on. Suppose one chapter1 element is removed in between, lets say > xn> second section, then the numbering should reset itself so that now the > xn> output looks like: > > xn> 1. first section > xn> 2. third section > xn> 3. fourth section > > xn> Is it possible to achieve this in xslt and XSLFO? > > xn> Please do let me know. > > xn> Thanks > > > -- > Alexey mailto:alexey.nikolaenkov@xxxxxxxxxxxx
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