RE: [xsl] Numbering: position() ?

["Michael Kay" <mike@xxxxxxxxxxxx>]

Then try <xsl:number level="any"/>

You can use position() if the apply-templates is

<xsl:apply-templates select="//page"/>

but not if you are doing a hierarchic tree walk.

Michael Kay
http://www.saxonica.com/ 

> -----Original Message-----
> From: Sven Waibel [mailto:sven.waibel@xxxxxxxx] 
> Sent: 10 January 2007 10:55
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: Re: [xsl] Numbering: position() ?
> 
> The right one should look like:
> 1.1
> 1.2
> 1.3
> 1.4
> 1.5
> 
> 
> Michael Kay wrote:
> > 1. The value of position() within an xsl:template depends on the 
> > position of the node within the set of nodes selected by the select 
> > expression of the corresponding xsl:apply-templates, which 
> you haven't shown us.
> > 
> > 2. You don't say what numbering you would consider correct. 
> If you're 
> > looking for multi-level numbering, try <xsl:number 
> level="multiple"/>. 
> > If you want single-level numbering, consider <xsl:number 
> level="any"/>.
> > 
> > Michael Kay
> > http://www.saxonica.com/
> >  
> > 
> >> -----Original Message-----
> >> From: Sven Waibel [mailto:sven.waibel@xxxxxxxx]
> >> Sent: 10 January 2007 10:41
> >> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> >> Subject: [xsl] Numbering: position() ?
> >>
> >> Hi,
> >>
> >> i got following xml:
> >>
> >> <book id="1">
> >> 	<page>
> >> 	<special>
> >> 		<page>
> >> 		<page>
> >> 	</special>	
> >> 	<page>
> >> 	<page>
> >> </book>
> >>
> >> xslt:
> >>
> >>
> >> <xsl:template match="page">
> >> 	<xsl:value-of select="concat(concat(ancestor::book/$id,
> >> '.'), position())"/> </xsl:template>
> >>
> >> I got this numbering:
> >> 1.1
> >> 1.1
> >> 1.2
> >> 1.3
> >> 1.4
> >>
> >> How can i achieve that the numbering is correct?
> >>
> >> Thanks
> >> Sven
> > 
> > 
> > 
> 
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