Re: [xsl] how to find parent node

[xslt.new <xslt.new@xxxxxxxxx>]

Hi:

If using name() is not a good idea, are there other ways to find the parent?

On 1/23/07, David Carlisle <davidc@xxxxxxxxx> wrote:
> > And I want to find out the parent of test1 in the <test1> template
> > itself. I tried <xsl:value-of select="name(parent::*)"/>. This works
> > only if <test1> is directly under <element1> and not under <para>
> >
>
> why do you say it doesn't work under para?
> If you execute that code when the current element is the test1 eleemnt
> in your example, it will return "para" which is the name of the parent.
> (although actually it's usually a bad idea to use the name() function)
>
> David