Subject: RE: [xsl] Simple Question From: "Michael Kay" <mike@xxxxxxxxxxxx> Date: Wed, 31 Jan 2007 09:56:08 -0000 |
It's actually a pretty deep question, though a very common one among beginners. XSLT doesn't "print out XML". It creates nodes in a result tree. The result tree is subsequently (and optionally) passed to a serializer, which "prints out" an XML representation of the tree. The problem isn't so much that your code is invalid XML, as that it shows a misunderstanding of the XSLT processing model. When you see in a stylesheet <a>....</a> that isn't an instruction to output a start tag, then do something (....), then output an end tag. It's a single indivisible instruction to output an element node named a, whose children are determined by the value of the expression (....). Later on, if you choose to serialize the result tree, the serializer looks at the element node and serializes it using a start tag and an end tag. As we've often remarked on this list, you can't create half a node. Michael Kay http://www.saxonica.com/ > -----Original Message----- > From: Punnoose, Roshan [mailto:punnooser@xxxxxxxxxxxxxxx] > Sent: 30 January 2007 20:56 > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject: [xsl] Simple Question > > I know that this is a really simple question but I just can't > seem to figure it out. I want to print out xml if a certain > condition is true, so I thought the bottom would work, but of > course it isn't valid xml. > Any ideas? > > <xsl:if test="$a != $times"> > <xqx:orOp> > <xqx:firstOperand> > </xsl:if> > > Roshan Punnoose > Phone: 301-497-6039
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