Subject: Re: [xsl] transforming without outputting original namespace From: Kamal Bhatt <kbhatt@xxxxxxxxx> Date: Mon, 05 Feb 2007 08:23:14 +1100 |
Can you run your output through a second transformation? If so, then run the output through this XSLT (this was originally sourced from http://cocoon.apache.org/2.1/faq/faq-xslt.html) :Thanks to David's help, I am now transforming xml that has a namespace. My target is a piece of HTML, so I would prefer if the namespace was not in the output, which it is:
<div xmlns="http://www.photoparata.com/events.xsd" xmlns:p="urn://www.photoparata.com/events.xsd" id="titlebar"/>
How do I go about getting rid of it?
<?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/> <xsl:template match="*"> <!-- remove element prefix (if any) --> <xsl:element name="{local-name()}"> <!-- process attributes --> <xsl:for-each select="@*"> <!-- remove attribute prefix (if any) --> <xsl:attribute name="{local-name()}"> <xsl:value-of select="."/> </xsl:attribute> </xsl:for-each> <xsl:apply-templates/> </xsl:element> </xsl:template> </xsl:stylesheet>
-- Kamal Bhatt
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