Subject: Re: [xsl] Doctype Declerations Imported StyleSheets From: "Manfred Staudinger" <manfred.staudinger@xxxxxxxxx> Date: Sat, 10 Feb 2007 21:01:27 +0100 |
XSLT 1.0Thanks, but still, which processor are you using to process your XSLT 1.0 ?
So it needs to be part of the child stylesheet? Do you know how this is specified in the docs so that I can keep my eyes open for this?
http://www.w3.org/TR/xslt#output says: The xsl:output element is only allowed as a top-level element.
XSLT 1.0 So it needs to be part of the child stylesheet? Do you know how this is specified in the docs so that I can keep my eyes open for this?
On 2/10/07, Manfred Staudinger <manfred.staudinger@xxxxxxxxx> wrote: > On 10/02/07, Karl Stubsjoen <kstubs@xxxxxxxxx> wrote: > > If I have a base template and I set the output to: > > > > <xsl:output method="html" indent="yes" > > doctype-public="-//W3C//DTD HTML 4.01//EN" > > doctype-system="http://www.w3.org/TR/html4/strict.dtd"/> > > > > Do I need to call out this doctype again in a template which imports > > this base template? It seems I do. If I don't, the resulting doctype > > is different than the doctype called out above. So how does this > > work? > What is the processor you are using ? > XSLT 1.0 or XSLT 2.0 ? > As the output element has to be a child of the stylesheet element, I think > you cannot have it in an importet template. > > Manfred
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
Re: [xsl] Doctype Declerations Impo, Karl Stubsjoen | Thread | Re: [xsl] Doctype Declerations Impo, Karl Stubsjoen |
Re: [xsl] Doctype Declerations Impo, Karl Stubsjoen | Date | Re: [xsl] Doctype Declerations Impo, Karl Stubsjoen |
Month |