Re: [xsl] Choosing based on current node

["Mukul Gandhi" <gandhi.mukul@xxxxxxxxx>]

I think Abel has given some good remarks.

But I think, your code fragment needs to be modified as:

<xsl:for-each select="A|B|C">
 <xsl:choose>
    <xsl:when test="self::A">
      <xsl:call-template name="do-A"/>
    </xsl:when>
    <xsl:when test="self::B">
      <xsl:call-template name="do-B"/>
    </xsl:when>
    <xsl:otherwise>
      <xsl:call-template name="do-C"/>
    </xsl:otherwise>
 </xsl:choose>
</xsl:for-each>

On 2/12/07, sthomas2@xxxxxxx <sthomas2@xxxxxxx> wrote:
> I'm amazed at how patient this list is with newbie questions; I hope
> this question doesn't try that patience too much. I'm processing a
> document that has <A> or <B> or <C> elements in it. I need to preserve
> their order in the output, but do something drastically different for
> each. It seems like the following ought to work, but, instead, the
> otherwise branch is always performed, regardless of whether the element
> is A, B, or C. (The for-each is working fine, as it correctly skips over
> any elements other than A, B, or C.)
>
> <xsl:for-each select="A|B|C">
>    <xsl:choose>
>        <xsl:when test=".=A">
>            <xsl:call-template name="do-A"/>
>        </xsl:when>
>        <xsl:when test=".=B">
>            <xsl:call-template name="do-B"/>
>        </xsl:when>
>        <xsl:otherwise>
>            <xsl:call-template name="do-C"/>
>        </xsl:otherwise>
>    </xsl:choose>
> </xsl:for-each>
>
> Thanks in advance,
>
> Stephen


--
Regards,
Mukul Gandhi