Subject: Re: [xsl] job for xsl:key? (XSL 1.0 question) From: "Dimitre Novatchev" <dnovatchev@xxxxxxxxx> Date: Wed, 21 Feb 2007 17:17:58 -0800 |
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:f="http://fxsl.sf.net/" xmlns:func-transform="f:func-transform" exclude-result-prefixes="f func-transform"
<xsl:import href="../f/func-transform-and-sum.xsl"/>
<xsl:template match="/"> <xsl:value-of select= "f:transform-and-sum(f:usrTrans(), /*/*/contact)"/> </xsl:template>
<xsl:function name="f:usrTrans" as="element()"> <func-transform:func-transform/> </xsl:function>
<xsl:template match="func-transform:*" mode="f:FXSL"> <xsl:param name="arg1"/> <xsl:sequence select="$arg1/root()/*/*/type[@value = $arg1/@type]/@benchmark1"/> </xsl:template> </xsl:stylesheet>
When this transformation is applied on the provided xml document (corrected to make it well-formed:
<t> <types> <type value="1" benchmark1="540" /> <type value="2" benchmark1="640" /> <type value="3" benchmark1="740" /> </types> <contacts> <contact type="1" /> <contact type="2" /> <contact type="3" /> <contact type="3" /> </contacts> </t>
Below is the corresponding XSLT 1.0 transformation, making use of the FXSL 1.2 tranform-and-sum template:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:func-transform="f:func-transform" exclude-result-prefixes="xsl func-transform"
<xsl:import href="transform-and-sum.xsl"/> <xsl:output method="text"/>
<xsl:template match="/"> <xsl:call-template name="transform-and-sum"> <xsl:with-param name="pFuncTransform" select="document('')/*/func-transform:*[1]"/> <xsl:with-param name="pList" select="/*/*/contact"/> </xsl:call-template> </xsl:template>
<xsl:template match="func-transform:*"> <xsl:param name="arg"/> <xsl:value-of select="$arg/ancestor::node()[last()]/*/*/type[@value = $arg/@type]/@benchmark1"/> </xsl:template> </xsl:stylesheet>
-- Cheers, Dimitre Novatchev --------------------------------------- Truly great madness cannot be achieved without significant intelligence. --------------------------------------- To invent, you need a good imagination and a pile of junk ------------------------------------- You've achieved success in your field when you don't know whether what you're doing is work or play
I could do the following easily by making a recursive template and then looping through the contacts, and passing on the corresponding benchmark value. But could xsl:key make for a shorter, more elegant solution?
Instead of performing an addition for each <contact>, could I simply sum() them at once, somehow?
With the following XML
<types> <type value="1" benchmark1="540" /> <type value="2" benchmark1="640" /> <type value="3" benchmark1="740" /> </types> <contacts> <contact type="1" /> <contact type="2" /> <contact type="3" /> <contact type="3" /> </contacts>
desired output:
<totals> <benchmark val='2660' /> </totals>
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