Subject: Re: [xsl] Looping a node in XSLT From: Senthilkumaravelan Krishnanatham <senthil@xxxxxxxxx> Date: Tue, 6 Mar 2007 19:09:23 -0800 |
Hi,
This is because "for $n in (1 to 10) return ." is an XPath 2.0 expression and can only be used in XSLT 2.0 stylesheets, whereas you're probably using a XSLT 1.0 processor.
Loana
On 3/6/07, Senthilkumaravelan Krishnanatham <senthil@xxxxxxxxx> wrote:I am not using Saxon 8.8 and use java parser to do the same. for loop syntax is nt working in there,
On Mar 6, 2007, at 5:39 PM, Abel Braaksma wrote:
> Senthilkumaravelan Krishnanatham wrote:
>>
>> Compiler warnings:
>> line 5: Illegal attribute 'select'.
>> ERROR: 'Syntax error in 'for 1 to 10 return .'.'
>> FATAL ERROR: 'Could not compile stylesheet'
>>
>> (Location of error unknown)XSLT Error
>> (javax.xml.transform.TransformerConfigurationException): Could not
>> compile stylesheet
>> Is there anyway I could use
>
>
> Yes, there were errors in my template, it's getting a bit late over
> here, but nothing unusual, just a few typos, easy enough to fix if
> you follow the syntax error messages. A fix (checked and compiled
> with Saxon 8.8):
>
> <xsl:template match="products">
> <xsl:copy><xsl:apply-templates select="customer" /></ xsl:copy>
> </xsl:template>
> <xsl:template match="customer">
> <xsl:copy-of select="for $n in (1 to 10) return ." />
> </xsl:template>
>
>
>
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