Subject: Re: [xsl] Universally quantified test of child attribute presence/absence From: Abel Braaksma <abel.online@xxxxxxxxx> Date: Tue, 20 Mar 2007 15:51:30 +0100 |
1) There are element children, and they all have the attribute.
2) Each of the element children, if any, does not have the attribute.
3) Some element children do have the attribute, some don't.
The solution I have found (thanks again to you and David) is to explicitly couple the existence of children with attribute presence for case 1, then proceed to case 2 where I just test for attribute absence before passing on to the "otherwise" clause representing case 3:
<xsl:choose> <xsl:when test="* and (every $child in * satisfies $child[@my_attribute])"> </xsl:when> <xsl:when test="every $child in * satisfies $child[not(@my_attribute)]"> </xsl:when> <xsl:otherwise> </xsl:otherwise> <xsl:choose>
Relying on the evaluation order of the instructions within xsl:choose spares me from having to use more complicated (or less familiar :-)) test expressions.
Note that for case 2, testing revealed that I can't test for
not(every $child in * satisfies $child[@my_attribute])
<xsl:choose> <xsl:when test="* and (every $child in * satisfies $child[@my_attribute])"> <!-- all children have @my_attribute --> </xsl:when> <xsl:when test="*[@my_attribute]"> <!-- some children have @my_attribute --> </xsl:when> <xsl:otherwise> <!-- zero children, or none have @my_attribute --> </xsl:otherwise> <xsl:choose>
Cheers, -- Abel Braaksma http://www.nuntia.nl
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