<-prev [Thread] next-> <-prev [Date] next->
Month Index | List Home

[xsl] Xsl:param from PHP to html

Subject: [xsl] Xsl:param from PHP to html
From: "Alan Hale" <alan.hale@xxxxxxxxxxx>
Date: Fri, 13 Apr 2007 16:03:18 +0100
I know I am doing something fundamentally wrong here, but I cannot
understand what. 

I am trying to pass a parameter to a stylesheet from PHP, and use it to
determine the sort order. I am sure the parameter is being assigned
correctly in the PHP code, but when I run the xsl below, I always get
the default value of $SORTBY.

Many thanks

Alan

<html 
	xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
	xsl:version='1.0'>
	
	  <!--Define parameter name and set default value-->
      <xsl:param name = "SORTBY">species_name</xsl:param>
      
 
  <body>
   

      <xsl:for-each select="/fieldguide/account">
     
      <xsl:sort select = "$SORTBY" order = "ascending"/>
      
         
	 <td align = "center"><xsl:value-of select="species_name"/></td>
	<td width = "40" align = "center"><xsl:value-of
select="has_text"/></td>
	<td width = "40" align = "center"><xsl:value-of
select="has_photo"/></td>
	<td width = "40" align = "center"><xsl:value-of
select="has_drawing"/></td>
	<td width = "40" align = "center"><xsl:value-of
select="has_map"/></td>
        <td align = "right"><xsl:value-of select="format_date"/></td>

      </tr>
      </xsl:for-each>
    </table>
  </body>
</html>

-- 
No virus found in this outgoing message.
Checked by AVG Free Edition.
Version: 7.5.446 / Virus Database: 269.4.0/759 - Release Date:
12/04/2007 19:58
Current Thread
<- PreviousIndexNext ->
Re: [xsl] Friday challenge: XSLT th, bryan rasmussen Thread Re: [xsl] Xsl:param from PHP to htm, Steve
Re: [xsl] Friday challenge: XSLT th, Andrew Welch Date Re: [xsl] Friday challenge: XSLT th, Andrew Welch
Month