Subject: RE: [xsl] RE: Question about grouping attributes using keys From: "Michael Kay" <mike@xxxxxxxxxxxx> Date: Mon, 23 Apr 2007 19:57:00 +0100 |
> Weird...in the Xpath specs, "A node test node() is true for > any node of any type whatsoever." > But in the XSLT specs, "node() matches any node other than an > attribute node and the root node" The NodeTest node() matches any node, but the expression node() is short for child::node() which only selects nodes that are children of something. > > Is there any way to select "any node of any type" in XSLT > 1.0? That would make things much easier. You can select nodes of any type, but you need to say which axis you want to use to find them. Attribute nodes are found only on the attribute axis, and there is no way of searching the attribute axis at the same time as another axis, except by using a "union" operator as you have done. Michael Kay http://www.saxonica.com/
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