|
Subject: RE: [xsl] Testing if all child nodes match (based on the value of certain elements) From: "Michael Kay" <mike@xxxxxxxxxxxx> Date: Mon, 23 Apr 2007 22:11:54 +0100 |
> <xsl:when test="not( group/person/age != group/person/age ) and > not( group/person/sex != group/person/sex )"> That's likely to be quite expensive if it's a large dataset: a better solution with XSLT 2.0 is count(distinct-values(group/person/age))==1 and count(distinct-values(group/person/sex))==1 Perhaps even better, given that you're dealing with siblings, is not(group/person[age=preceding-sibling::person[1]/age and sex=preceding-sibling::person[1]/sex]) which also works in 1.0. But the performance of the different constructs depends on the optimizer, on the size of the dataset, and also on the probability of the condition being true. Michael Kay http://www.saxonica.com/
| Current Thread |
|---|
|
| <- Previous | Index | Next -> |
|---|---|---|
| Re: [xsl] Testing if all child node, G. Ken Holman | Thread | Re: [xsl] Testing if all child node, David Carlisle |
| Re: [xsl] Testing if all child node, Abel Braaksma | Date | Re: [xsl] Testing if all child node, David Carlisle |
| Month |