Re: [xsl] variable in xsl:template match

Subject: Re: [xsl] variable in xsl:template match
From: Abel Braaksma <abel.online@xxxxxxxxx>
Date: Thu, 26 Apr 2007 16:52:58 +0200
Garvin Riensche wrote:
Great! Thanks to you an Ronan for the quick answer!

/root/node()[name() = $target]/child


Be aware of namespaces... You may want to use local-name() or some other method, as in my previous post. Also, you need XSLT 2.0, but that was already explained to you.


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