Subject: Re: [xsl] make it single line From: Wendell Piez <wapiez@xxxxxxxxxxxxxxxx> Date: Thu, 03 May 2007 12:35:33 -0400 |
#1 <xsl:stylesheet ...>
<xsl:template match="/"> <xsl:copy-of select="/"/> </xsl:template>
Cheers, Wendell
Start with a recursive copy template then match the text nodes and process the new lines, for instance replace them with spaces:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:template match="node() | @*"> <xsl:copy> <xsl:apply-templates select="node() | @*"/> </xsl:copy> </xsl:template> <xsl:template match="text()"> <xsl:value-of select="translate(., ' ',' ')"/> </xsl:template> </xsl:stylesheet>
Best Regards, George --------------------------------------------------------------------- George Cristian Bina - http://aboutxml.blogspot.com/ <oXygen/> XML Editor, Schema Editor and XSLT Editor/Debugger http://www.oxygenxml.com
Senthilkumaravelan K wrote:Hi
I want to flatten the XML node structure to single line,
I tried indent=no and it does not work for me.
Please any suggestions.
I use the following xslt
<?xml version="1.0" encoding='UTF-8'?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="no" />
<xsl:template match="*">
<xsl:copy>
<xsl:apply-templates/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
input
<node1>
</Item1>
</Item1>
</Item1>
</Item1>
</Item1>
</Item1>
</Item1>
</node1>
output
<node1></Item1></Item1></Item1>..</node1>
Regards,
Senthil
====================================================================== Wendell Piez mailto:wapiez@xxxxxxxxxxxxxxxx Mulberry Technologies, Inc. http://www.mulberrytech.com 17 West Jefferson Street Direct Phone: 301/315-9635 Suite 207 Phone: 301/315-9631 Rockville, MD 20850 Fax: 301/315-8285 ---------------------------------------------------------------------- Mulberry Technologies: A Consultancy Specializing in SGML and XML ======================================================================
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