Subject: [xsl] order as defined in the sequence From: Merico Raffaele <raffaele.merico@xxxxxxx> Date: Wed, 23 May 2007 14:48:40 +0200 |
Dear Community Is there any possibility to set the order of the selected nodes as defined in the sequence. I.E. <xsl:for-each select="/node[@class = ('z', 'a', 'b')]"> I would like to process the nodes exactly as defined in the sequence z-a-b, that means: 1) node[@class eq 'z'] 2) node[@class eq 'a'] 3) node[@class eq 'b'] Or do I have to use 3 <xsl:apply-templates/>. For your support many thanks in advance ... Raffaele
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