Subject: Re: [xsl] XPath MOD 10 calculation From: "Andrew Welch" <andrew.j.welch@xxxxxxxxx> Date: Fri, 25 May 2007 10:16:30 +0100 |
> <xsl:variable name="calc" select="(10 - ((sum($odd) * 3) + > sum($even)) mod 10) mod 10" as="xs:integer"/> > <xsl:if test="$calc ne $check-digit">UPC not legal</xsl:if>
foo mod 10 mod 10 is the same as foo mod 10, and 10 mod 10 is 0 so the above is
<xsl:if test="($check-digit + ((sum($odd) * 3) + sum($even))) mod 10 =0">
to give you the check-digit? If so it makes the outermost "mod 10" of $calc redundant? (if it is then step #4 on the wikipedia article isnt needed)
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