Re: [xsl] How to get element name for output

["Eric Larson" <ionrock@xxxxxxxxx>]

There is also local-name() if for some reason you want to do get the
name without a namespace prefix. I could be misunderstanding how
local-name() works compared to name(), but hopefully someone else can
clarify if I am wrong about that.

Eric

On 6/6/07, Michael Kay <mike@xxxxxxxxxxxx> wrote:
> You can get the name of a node using the XPath name() function, for example
>
> <attribute type="{name()}"/>
>
> Michael Kay
> http://www.saxonica.com/
>
>
> > -----Original Message-----
> > From: Chaudhary, Harsh [mailto:HCHAUDHA@xxxxxxxxx]
> > Sent: 06 June 2007 22:33
> > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> > Subject: [xsl] How to get element name for output
> >
> > Hi,
> >
> > I am writing XSLt (ver 1.0) for output to an XML file. At one
> > point I would like to get the name of the element and include
> > that in the output. An example would be:
> >
> > Input XML:
> >
> > <rootElement>
> >         <productAttributeList>
> >             <attributeMap>
> >                 <ReinstatementInProc>N</ReinstatementInProc>
> >             </attributeMap>
> >             <elementName>attribute</elementName>
> >         </productAttributeList>
> > </rootElement>
> >
> > Output XML:
> >
> > <rootElement>
> >     <attribute type="ReinstatementInProc">N</attribute>
> > </rootElement>
> >
> > I would really appreciate your help on this.
> >
> > Thanks,
> > Harsh.