Re: [xsl] Sorting by document order of some other element

["Peter Hunsberger" <peter.hunsberger@xxxxxxxxx>]

On 6/25/07, David Carlisle <davidc@xxxxxxxxx> wrote:

> <xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
> <xsl:key name="k" match="set2/*" use="@id"/>
> <xsl:output indent="yes"/>
>   <xsl:template match="doc">
>     <set2>
>       <xsl:copy-of select="for $e in set1/* return key('k',$e/@id)"/>
>     </set2>
>   </xsl:template>
> </xsl:stylesheet>

David, that's a cool solution.  Unfortunately I glossed over the fact
that there is some manipulation of the data within the second set
going on.  I'm going to experiment with trying this approach within a
for-each and/or apply-template. as well as attempting to invert the
problem as suggested by Eric.


--
Peter Hunsberger