Hello everyone,
I have searched everywhere for a similar problem but most problems are
actually very simple with simple solutions. But the techniques are the same.
Except I cant seem to put differenct peices together. When i run my XSL, the
desired result is not desired! :)
The Objective:
Remove truly duplicate elements, not just by name but by its attributes and
attribute values.
The Example:
I have an xml input file (which is actually an XSD) with various
<xsd:element>'s which may have many attributes.
The attributes I care about are "name" and "type". Below is a sample input
file:
<xsd:element name="ABC" type="123" ... >
<xsd:element name="def" type="456" .../>
<xsd:element name="ghi" type="456" .../>
</xsd:element>
<xsd:element name="ABC" type="456" ...>
<xsd:element name="ghi">
<xsd:element name="def" type="456" .../>
<xsd:element name="def"/>
</xsd:element>
<xsd:element name="ABC"/>
<xsd:element name="ABC"/>
<xsd:element name="ghi" type="456" .../>
</xsd:element>
The desired result should be a flat list of elements:
<uniqueElements>
<element name="ABC"/>
<element name="ABC" type="123"/>
<element name="ABC" type="456"/>
<element name="def"/>
<element name="def" type="456"/>
<element name="ghi"/>
<element name="ghi" type="456"/>
</uniqueElements>
The order of the result doesn't matter. But understand that all those
elements are distinctly unique. I'm using Xalan Java 2.7/XPath 1.0.
My XSL Logic:
Since i need a flat list i will interate through "//xsd:element".
So, for every element encountered, check to see if there are any elements
before it with the same name, and same type.
Sounds simple enough! But it isn't. I cant get the right combination of
conditional logic with correct XPath syntax to execute this task. Maybe this
task can not be done at all? I would like to know first if I'm wasting my
time trying to figure this out or if there is any hope.
Please help as I'm sure this will benefit anyone else wanting to do the same
task. Thank you!
Wasiq Shaikh
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