Subject: RE: [xsl] Flat XML to hierarchical output ... From: "Michael Kay" <mike@xxxxxxxxxxxx> Date: Mon, 20 Aug 2007 23:43:28 +0100 |
Search for "XSLT positional grouping". In XSLT 2.0, use <xsl:for-each-group group-starting-with="HEADER"> Michael Kay http://www.saxonica.com/ > -----Original Message----- > From: Tim Dexter [mailto:timothy.dexter@xxxxxxxxx] > Sent: 20 August 2007 23:36 > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject: [xsl] Flat XML to hierarchical output ... > > Hi All > > I have the following data structure > > <REPORT> > <HEADER> > ... > </HEADER> > <LINE> > ... > </LINE> > <TOTAL> > ... > </TOTAL> > <HEADER> > ... > </HEADER> > <LINE> > ... > </LINE> > <TOTAL> > ... > </TOTAL> > <HEADER> > ... > </HEADER> > <LINE> > ... > </LINE> > <LINE> > ... > </LINE> > <LINE> > ... > </LINE> > <TOTAL> > ... > </TOTAL> > </REPORT> > > Although the XML is not hierarchical there is a hierarchy > required in output ie HEADER LINES TOTAL > > the only thing that is guaranteed is that the data is in > sequential hierarchy order ie HEADER is followed by LINES by > TOTAL. Notice that there maybe 1 or more instances of LINE > following HEADER ie multi lines for a given header. > > I have tried loading the HEADER-LINE-TOTAL trees into > variables, then looping thru the HEADER and grabbing LINE and > TOTAL values based on the HEADER record position(). Of course > a ll is fine until I hit a HEADER with multiple lines. > > I'm still trying this but if anyone has come across and > solved a similar problem I'd greatly appreciate any input > > Thanks > > tim
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