Subject: RE: [xsl] [XSL]Display Different Results Based on Count ofNodeSets From: "Michael Kay" <mike@xxxxxxxxxxxx> Date: Mon, 24 Sep 2007 12:39:03 +0100 |
Please start again at the beginning. Few people are going to try to analyze your previous messages to work out what you mean my "as described previously" or "the one I posted earlier". Just give us a source document, a stylesheet, the output you are getting, and the output you want. Please make each of them complete, but brief: don't post fragments, and don't refer back to previous postings. Michael Kay http://www.saxonica.com/ > -----Original Message----- > From: Alice Ju-Hsuan Wei [mailto:ajwei@xxxxxxxxxxx] > Sent: 24 September 2007 12:18 > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject: RE: [xsl] [XSL]Display Different Results Based on > Count ofNodeSets > > Hi, > > This is what I got for the output (I am actually using > XSLT to transform into HTML, so the XML, as described > previously, was that > input) > > The output, oddly, when I used <xsl:value of > select="count(title)"/> instead of position() it produced 2 > and 1, respectively, but when the <xsl:apply-templates was > inserted, it generates output of > > <div><p>Tennison, Jeni.</p> > <p><i>Beginning XSLT</i>.</p> > <p><i>Begining XSLT 2.0</i>.</p></div> > > <div><p>Meyer, Eric.</p> > <p><i>The Zen of CSS</i>.</p> > </div> > > When I used the one I posted earlier: > > <xsl:template match="title"> > <xsl:choose> > <xsl:when test="position() ='1'"/> > <xsl:otherwise> > <p> > <xsl:apply-templates/> > > </p> > </xsl:otherwise> > </xsl:choose> > </xsl:template> > > It brings back the same input. However, I wanted the one on > the first of the <title> to be something like: > > <div><p>Tennison, Jeni. <i>Beginning XSLT</i>.</p> > <p><i>Begining XSLT 2.0</i>.</p></div> > > <div><p>Meyer, Eric. <i>The Zen of CSS.</i></p></div> > > > Is there some way I can do this? > > Many thanks. > > Alice
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