RE: [xsl] XSL Help

["Joe Fawcett" <joefawcett@xxxxxxxxxxx>]

There are a few options, with your current style use <xsl:value-of 
select="../Name"/>, the .. means use the parent, Customer, then choose the 
child Name. I think a better way would be to select only the Customer 
elements with a status: <xsl:for-each select="Customers/Customer[Status]"> 
to start with then just output Name and Status.

Joe
http://joe.fawcett.name


> From: "Waqar Ali" <waqarali_pk@xxxxxxxxxxx>
> Reply-To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: [xsl] XSL Help
> Date: Mon, 01 Oct 2007 11:31:17 -0400
>
> <Customers>
> 	<Customer>
> 		<Name>Joe Smith</Name>
> 		<Status>VIP</Status>
> 	</Customer>
> 	<Customer>
> 		<Name>Mary J</Name>
> 	</Customer>
> 	<Customer>
> 		<Name>John Hopkins</Name>
> 		<Status>VVIP</Status>
> 	</Customer>
> </Customers>
>
> Generate a list of records with Status:
> 	<xsl:template name="SPECIAL" match="/">
> 		<xsl:for-each select="Customers/Customer/Status">
> 			<xsl:value-of select="/Name"/>
> 			<xsl:text>-</xsl:text>
> 			<xsl:value-of select="/Status"/>
> 		</xsl:for-each>
> 	</xsl:template>
>
> The names/status are not getting printed. How can I move one level up to 
> print
> the names using value-of.
>
> Desired Output:
> 	Joe Smith-VIP
> 	John Hopkins-VVIP