Re: [xsl] Sorting Two Dimensional Table

[Martin Honnen <Martin.Honnen@xxxxxx>]

Pierre-Luc Bertrand wrote:

> Thanks for that answer but unfortunately, I can't get it to work. I
> don't know if it is due to the fact that I'm using Internet Explorer to
> see the transform but I'm getting this error:
>
> 'Reference to variable or parameter 'k1' must evaluate to a node list.'

> <xsl:stylesheet version="2.0"
> xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
> 		xmlns:xs="http://www.w3.org/2001/XMLSchema";
> 		exclude-result-prefixes="xs">
>   
>   <xsl:variable name="k1" as="xs:string+">
>     <xsl:perform-sort select="x/titles/key">
>       <xsl:sort select="."/>
>     </xsl:perform-sort>
>   </xsl:variable>

The stylesheet uses XSLT 2.0 so running it with IE which only supports 
XSLT 1.0 does not work.


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	Martin Honnen
	http://JavaScript.FAQTs.com/