Subject: [xsl] string parsing and delimiters From: "pat springer" <patspringer2007@xxxxxxxxxxxxxx> Date: Fri, 26 Oct 2007 12:19:24 +0100 |
Hello, I need to transform the following XML <Salaries Range = "B" Scale="7" Amount = "12050.30; 11058.23; 11251.25> with n 'Amount' values delimited by ';' into three n XML elements: <Salaries Range = "B" Scale="7" Amount = "12050.30"> <Salaries Range = "B" Scale="7" Amount = "11058.23"> <Salaries Range = "B" Scale="7" Amount = " 11251.25"> Any help with that. thanks. Pat.
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
Re: [xsl] 'number-rows-spanned' doe, J.Pietschmann | Thread | RE: [xsl] string parsing and delimi, Michael Kay |
RE: [xsl] Re: XSL to ODF/OOXML, W Charlton | Date | RE: [xsl] string parsing and delimi, Michael Kay |
Month |