Re: [xsl] normalize-space processing all nodes hack?

[Abel Braaksma <abel.online@xxxxxxxxx>]

From what you are writing I understand you are using XSLT 1.0, because 
in XSLT 2.0 your expression would give an error.

The way to do this is simply:

select = "normalize-space(A)"

which will give you the text content of node A (and thus of all its 
children).

HTH,
Cheers,
-- Abel Braaksma


Kolacm Toma9 wrote:
>  Hi!
>
>  I'd like to fill variable textOnly by normalized string of all text of the element A. I'm just wondering is there any way, I could write it as one XPath expression, like:
>
>  <xsl:variable name="textOnly" select="normalize-space(A//text())"/>
>
> (but here only the first text node is used)?
>
>  Please note, I'm interested only in the "one XPath expression" way, I know how solve problem in different way*.
>
>  Thanks, Tomas
>
> *like:
>
> <xsl:variable name="textOnlyPre">
>      <xsl:copy-of select="A//text()">
> </xsl:variable>
> <xsl:variable name="textOnly" select="normalize-space($textOnlyPre)"/>