Re: [xsl] Find the node with maximum elements

["Mukul Gandhi" <gandhi.mukul@xxxxxxxxx>]

On 11/4/07, G. Ken Holman <gkholman@xxxxxxxxxxxxxxxxxxxx> wrote:
> Which is what I already indicated in my response:
>
> At 2007-11-03 15:19 -0400, G. Ken Holman wrote:
> >You can optimize the speed by putting the max value into a variable
> >and testing against that

Sorry, Ken. Unfortunately, I didn't read your post completely.

> <?xml version="1.0" encoding="US-ASCII"?>
> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
>                 version="2.0">
>
> <xsl:output method="text"/>
>
> <xsl:template match="/">
>   <xsl:value-of select="/Sample/*[count(Car)=max(/Sample/*/count(Car))]
>                         /name(.)"
>                 separator="&#xa;"/>
> </xsl:template>
>
> </xsl:stylesheet>

This solution is nice. But if the OP wants to do something else with
the result (not just printing the result (sequence), as this solution
demonstrates), then I think xsl:for-each loop will be necessary.

-- 
Regards,
Mukul Gandhi