Subject: Re: [xsl] Using a sequence of years to select documents to display in a table row From: "G. Ken Holman" <gkholman@xxxxxxxxxxxxxxxxxxxx> Date: Fri, 23 Nov 2007 16:20:44 -0500 |
I have a working solution, but I don't think it makes good use of the language.
The years right now extend from 1842 through 1862.
I tried <xsl:for-each select="1842 to 1862"> <tr><td><xsl:value-of select="."/></td> <td> <xsl:apply-templates select="documents/document[year = . and contains(title, 'Selectmen')"/> </td> <td> <xsl:apply-templates select="documents/document[year = . and contains(title, 'School')"/> </td> </tr> </xsl:for-each>
The template that matches document just displays the value of each title element followed by a <br />
But, I get an error that I can't use documents in that way because the context is atomic.
I was able to get the following to work, basically hand-coding one row for each of the year values.
<tr><td>1859</td> <td><xsl:apply-templates select="documents/document[year = 1859 and contains(title, 'Selectmen')]"/></td> <td><xsl:apply-templates select="documents/document[year = 1859 and contains(title, 'School')]"/></td> </tr>
(repeat this for each year)
But there must be a direct way to do this with the language.
<xsl:variable name="docs" select="documents/document"/> <xsl:for-each select="1842 to 1862"> <tr><td><xsl:value-of select="."/></td> <td> <xsl:apply-templates select="$docs[year = . and contains(title, 'Selectmen')"/> </td> <td> <xsl:apply-templates select="$docs[year = . and contains(title, 'School')"/> </td> </tr> </xsl:for-each>
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