Subject: Re: [xsl] Select Parent when child exists From: "Andrew Welch" <andrew.j.welch@xxxxxxxxx> Date: Tue, 27 Nov 2007 10:38:03 +0000 |
On 27/11/2007, Tim Gaunt <info@xxxxxxxxxxxxxxxxxxx> wrote: > Hi, > > I'm trying to select all the parents that have a child node matching a > certain value. It's basically transforming a blog RSS feed and I only want > to select those posts that have a specific tag. > > The feed looks like this: > <feed> > <post> > <title>Title of the post 1</title> > <tags> > <tag>example</tag> > </tags> > </post> > <post> > <title>Title of the post 2</title> > <tags> > <tag>example2</tag> > </tags> > </post> > <post> > <title>Title of the post 3</title> > <tags> > <tag>example</tag> > <tag>example3</tag> > </tags> > </post> > </feed> > > In this example I want posts 1 and 3. > > I've had a Google around but I've not found any definitive answer. I was > thinking of an if statement but I would like to look the latest x posts and > I'm not sure how I can do that using an if statement as postion() is > incremental regardless of the quantifier. If you mean, "how do you select all <post> elements that contain a child <tag> element with the value 'example' " then then its: select="post[tags/tag = 'example']" -- Andrew Welch http://andrewjwelch.com Kernow: http://kernowforsaxon.sf.net/
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