Re: [xsl] recursive sorting by element name

["G. Ken Holman" <gkholman@xxxxxxxxxxxxxxxxxxxx>]

At 2007-11-28 17:04 -0500, Davis Ford wrote:
> Hi, consider the following example:
> ...
> I want to sort it as such
> ...
> I am trying to come up with a generic XSLT solution that does not use
> explicit element names, but only uses the sort select="name()", and it
> should be recursive such that if say, element <A1> contained further
> elements, then they would also be sorted by element name.
>
> Finally, if the element names are the same, then it should sort them
> by an attribute called "typeName".
>
> Can anyone provide some help?  Thank you in advance!

Am I missing something?  This is a variant of a one-template identity 
transform.

I hope the example below helps.

. . . . . . . . . . Ken

t:\ftemp>type davis.xml
<Collection>
  <CollectionB>
     <B2></B2>
     <A2></A2>
     <A1></A1>
     <B1 typeName="2"></B1>
     <B1 typeName="1"></B1>
  </CollectionB>
  <CollectionA>
     <B2></B2>
     <A2></A2>
     <A1></A1>
     <B1></B1>
  </CollectionA>
</Collection>

t:\ftemp>type davis.xsl
<?xml version="1.0" encoding="US-ASCII"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
                version="1.0">

<xsl:output indent="yes"/>
<xsl:strip-space elements="*"/>

<xsl:template match="@*|node()">
  <xsl:copy>
    <xsl:apply-templates select="@*|node()">
      <xsl:sort select="name(.)"/>
      <xsl:sort select="@typeName"/>
    </xsl:apply-templates>
  </xsl:copy>
</xsl:template>

</xsl:stylesheet>
t:\ftemp>xslt davis.xml davis.xsl con
<?xml version="1.0" encoding="utf-8"?>
<Collection>
   <CollectionA>
      <A1/>
      <A2/>
      <B1/>
      <B2/>
   </CollectionA>
   <CollectionB>
      <A1/>
      <A2/>
      <B1 typeName="1"/>
      <B1 typeName="2"/>
      <B2/>
   </CollectionB>
</Collection>
t:\ftemp>




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