Subject: Re: [xsl] grouping problem|
From: "G. Ken Holman" <gkholman@xxxxxxxxxxxxxxxxxxxx>
Date: Wed, 28 Nov 2007 17:54:54 -0500
I do have a more general question/clarification that perhaps someone can address.
Say I want to replace an element and its attributes with a new element name and attribute(s). Say I also want to keep the mark-up of the content. I have noticed that if I use <xsl:value-of select "."/> the content mark-up is stripped out. So with this content:
<test> <selection name="u1pt01"> <para> text, more text, <i>italic text.</i> </para> </selection>
The following template would strip out the <i> tags,
<xsl:template match="selection"> <para aim:pstyle='bodytext'><xsl:value-of select "para"/><para> </xsl:template>
<test> <selection name="u1pt01"> <para aim:pstyle='bodytext'> text, more text, italic text. </para> </selection>
Am I correct?
To avoid stripping content mark-up, I need to use <xsl:copy-of select "para"/>. When I do that, however, I get two <para> tags.
With copy-of, is it still possible to replace elements and attributes?
I suspect that I am missing something very basic. Some clarification would be great.
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