Re: [xsl] How to read Schema XSD in stylesheet XSL!

[Eliot Kimber <ekimber@xxxxxxxxxxxx>]

Abel Braaksma wrote:

> In all honesty, all you need is an XML processor that supports Schema 
> processing. You do not need any XSLT. But if you are determined to use 
> XSLT, just use XSLT 2.0 with validation (available with Saxon-SA and 
> AltovaXML, the latter free). If the content is valid, output "yes", if 
> not,. output "no". For all that I know, you can write any stylesheet (as 
> long as validation is on) and let it output something. If the output is 
> nothing or an error or a different exit code, you let your calling 
> process (i.e., a batch file or a workflow system) output "no". Or, like 
> Wendell suggested, use the extension functions of Saxon.

Note that you don't need SaxonSA to do schema-validated XSLT processing 
of documents, you just need to use a parser that is both schema-aware 
(e.g., Xerces) and is configured to do schema validation. This requires 
a small bit of Java code or doing the necessary Java system property 
configuration to set it up.

What you need SaxonSA for is to do schema *aware* XSLT processing such 
that you can refer to data types and complex types defined in your 
schema in your XSLT templates.

Cheers,

Eliot

--
Eliot Kimber
Senior Solutions Architect
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