Subject: Re: [xsl] current-group() question From: David Carlisle <davidc@xxxxxxxxx> Date: Thu, 6 Dec 2007 13:57:13 GMT |
<xsl:when test="current-group()/p"> That tests as true if any item in the current group has a p child. In your example all the items are p or b children of <root> and none of them have a p child, so it always tests as false. You want "current-group()/self::p which asks if any item is a p rather tahn having a p child, or since that is essentially your grouping key you can just use test="curent-grouping-key()" David ________________________________________________________________________ The Numerical Algorithms Group Ltd is a company registered in England and Wales with company number 1249803. The registered office is: Wilkinson House, Jordan Hill Road, Oxford OX2 8DR, United Kingdom. This e-mail has been scanned for all viruses by Star. The service is powered by MessageLabs. ________________________________________________________________________
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