Re: [xsl] loading and unloading xml files using xslt

["Senthil Nathan" <rsennat@xxxxxxxxx>]

It's not that. I would like to load all the nodes from "b.xml"
and then after some operation, I would like to remove the same nodes
which was added from "b.xml".

On Dec 19, 2007 12:17 AM, Alice Wei <ajwei@xxxxxxxxxxx> wrote:
> Hi,
>
>   I have a suggestion here although I am not sure if this is what you
> are trying to do.
>
>   If you want to just load some file by looking for specific nodes
> according to their occurrences, you might want to put in <xsl:if>
> statements, and if the parameter is true, you can do something like
> <xsl:include href="xslt_example_template.xsl" />. If else, then don't
> put in anything.
>
> I hope this helps.
>
> Alice
>
>
> Quoting Senthil Nathan <rsennat@xxxxxxxxx>:
>
> > Hi,
> > I would like to know how to load / unload xml files from the main xml file.
> >
> > ie. say there is "a.xml", to which I load "b.xml". (means i see the
> > leaf nodes in b.xml
> > and append those in the a.xml").
> > Now, I would like to unload "b.xml" from this. (ie., remove those
> > nodes added earlier).
> > I know this can be done by looking for those specific nodes and remove
> > it the way i added
> > the child.
> >
> > My question here is, whether all this load / unload can be done using xslt???
> >
> > Thanks
> > Senthil
> >
> >
>
>
>
> Alice Wei
> MIS 2008
> School of Library and Information Science
> Indiana University Bloomington
> ajwei@xxxxxxxxxxx
> 812-856-2659