Subject: Re: [xsl] xalan and replace "regex" From: "Matthew L. Avizinis" <mla@xxxxxxxxx> Date: Thu, 27 Dec 2007 19:00:16 -0500 |
Matthew L. Avizinis wrote: > also check out: > http://xml.apache.org/xalan-j/extensionslib.html#exslt > http://www.exslt.org for examples > > Mansour wrote: > >> Hello: >> Is there any way I can use replace with xalan. I have tried every >> thing possible but couldn't get it to work: >> >> <?xml version="1.0" encoding="UTF-8" ?> >> <xsl:stylesheet version="2.0" >> xmlns:xsl="http://www.w3.org/1999/XSL/Transform" >> xmlns:xalan="http://xml.apache.org/xalan" >> xmlns:str="http://exslt.org/strings"> >> <xsl:import href="str/str.xsl" /> >> <xsl:template match="program"> >> <xsl:value-of select="replace(.,'public','<KeyWord> pulic >> </KeyWord>')" /> >> </xsl:template> >> </xsl:stylesheet> >> >> >> >> >> I need to scan a piece of java code and be able to highlight the words >> based on their meaning. Anyone had luck with xalan regex ?? or >> analyze-string ??
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