Re: [xsl] Copy Child Elements

["Rick Quatro" <frameexpert@xxxxxxxxxxxx>]

Hi Abel,

Thanks for the excellent advice. I do need to use position() on the p 
element because the id attribute changes for each entry. So, I am using 
this:

<xsl:template match="p[position()=1]">
 <dt>
   <xsl:copy-of select="text()|*" />
 </dt>
</xsl:template>

<xsl:template match="p[position()=2]">
 <dd>
   <xsl:copy-of select="text()|*" />
 </dd>
</xsl:template>

Thanks again. And thanks to the others who replied.

Rick Quatro
Carmen Publishing
585-659-8267
www.frameexpert.com


> Don't use for-each here. Instead, use
>
> <xsl:apply-templates select="p" />
>
> and follow up with matching templates like the following. The last one is 
> a so-called throw-away template, it will be called when a <p> matches that 
> did not match any more specific match:
>
> <xsl:template match="p[id='Field_ShowAuthorJobTitle']>
>    <dt>
>        <xsl:copy-of select="text() | *" />
>    </dt>
> </xsl:template>
>
> <xsl:template match="p[id='Desc_ShowAuthorJobTitle']>
>    <dd>
>        <xsl:copy-of select="text() | *" />
>    </dd>
> </xsl:template>
>
> <!-- throw away other <p> elements -->
> <xsl:template match="p" />