[xsl] RE: first n nodes from a current-group

["Manish_Jaiswal" <Manish_Jaiswal@xxxxxxxxxx>]

Thank you very much Michael. It's working.

Regards,
Manish

-----Original Message-----
From: Michael Kay [mailto:mike@xxxxxxxxxxxx]
Sent: Thursday, February 07, 2008 7:06 PM
To: Manish_Jaiswal; xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: RE: first n nodes from a current-group

>
> But I wanted only the first two name elements having highest counts.
> that is output like:
>

Try

<School>
  <xsl:for-each-group select=" School/student
                      group-by="name/tokenize(., ';\s*')">
    <xsl:sort data-type="number" select="count(current-group())"
order="descending" />
    <xsl:sort select="current-grouping-key()"/>
    <xsl:if test="position() <= 2">
      <name count="{count(current-group())}">
        <xsl:value-of select="current-grouping-key()"/>
      </name>
    </xsl:if>
  </xsl:for-each-group>
</School>

Michael Kay
http://www.saxonica.com/





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