Re: [xsl] defining output document type by stylesheet parameters

["G. Ken Holman" <gkholman@xxxxxxxxxxxxxxxxxxxx>]

At 2008-02-18 11:04 -0600, James Sulak wrote:
> In XSLT 2.0, is it possible to define the output document type by
> stylesheet parameters?

Yes, not with <xsl:output> but with <xsl:result-document> ... most of 
the attributes of <xsl:result-document> are attribute value 
templates, where none of the <xsl:output> ones are.

> ...
> I know this type of thing wasn't possible in 1.0, but it seems like it
> might be in 2.0.  Is there another approach I should be using, or am I
> out of luck?  I'm using Saxon 9B.

I hope the example below helps.

. . . . . . . . . . Ken

X:\samp>type resultdoc.xsl
<?xml version="1.0" encoding="US-ASCII"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
                version="2.0">

<xsl:output indent="yes"/>

<xsl:variable name="test">test.ent</xsl:variable>

<xsl:template match="/">
  <xsl:result-document doctype-system="{$test}">
    <hello/>
  </xsl:result-document>
</xsl:template>

</xsl:stylesheet>
X:\samp>xslt2 resultdoc.xsl resultdoc.xsl t:\j.xml

X:\samp>type t:\j.xml
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE hello
  SYSTEM "test.ent">
<hello/>
X:\samp>



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