Subject: Re: [xsl] Style sheet to perform namespace mapping from input to output From: "Andrew Welch" <andrew.j.welch@xxxxxxxxx> Date: Tue, 25 Mar 2008 10:40:12 +0000 |
It wasn't meant to be copied verbatim :) "old" refers to your N namespace and "new" refers to N+1. If your elements weren't prefixed then you'll need to invent a prefix mapped to the existing namespace, such as "old", and then put all result elements in the new namespace, using: ( xmlns:old="the N namespace" defined on the root element) <xsl:template match="old:*"> <xsl:element name="{local-name(.)}" namespace="the N+1 namespace"> <xsl:copy-of select="@*"/> <xsl:apply-templates/> </xsl:element"> </xsl:template> You don't need the namespace attribute on xsl:element if you've already defined the default namespace on the root element, but personally I like it there. On 24/03/2008, Farrukh Najmi <farrukh@xxxxxxxxxxxxxxxxxxxxx> wrote: > Thanks David. The resulting style sheet gives an error similar to: > > ERROR: 'Namespace for prefix 'new' has not been declared.' > > I am assuming that I need to somehow add the 'new' namespace declaration > via 'xmlns:new ' attribute in result tree. > > This is probably a dumb question but how do I replace xmlns:old > namespace declaration with xmlns:new namespace declaration? > > Thanks again for your kind help. > > > David Carlisle wrote: > > declare old and new prefixes on xsl:stylesheet, then something like > > > > <xsl:template match="old:*"> > > <xsl:element name="new:{local-name(.)"> > > <xsl:copy-of select="@*"/> > > <xsl;apply-templates/> > > </xsl:element"> > > </xsl:template> > > > > > > -- > Regards, > Farrukh Najmi > > Web: http://www.wellfleetsoftware.com > > -- Andrew Welch http://andrewjwelch.com Kernow: http://kernowforsaxon.sf.net/
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