RE: [xsl] Splitting files 5 at a time

["Houghton,Andrew" <houghtoa@xxxxxxxx>]

> From: David Carlisle [mailto:davidc@xxxxxxxxx]
> Sent: 02 April, 2008 14:37
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: Re: [xsl] Splitting files 5 at a time
>
>
>
>    [count() mod 5 = 0]
>
> [position() mod 5 = 1]

I thought I understood his problem to be that he wanted the
first five customers in one file, then the next five customers
in the next, etc.  If he just did what you suggested wouldn't
he just grab every 1 in 5 customers out of the group of five
customers?

Customer  1 => position() mod 5 = 1
Customer  2 => position() mod 5 = 2
Customer  3 => position() mod 5 = 3
Customer  4 => position() mod 5 = 4
Customer  5 => position() mod 5 = 0

Customer  6 => position() mod 5 = 1
Customer  7 => position() mod 5 = 2
Customer  8 => position() mod 5 = 3
Customer  9 => position() mod 5 = 4
Customer 10 => position() mod 5 = 0

So if I understood your solution, he would create the first file
with Customer 1, 6, 11, 16, 21 and not Customer 1, 2, 3, 4, 5.
Is that correct?


Andy.