Subject: Re: [xsl] Splitting files 5 at a time From: David Carlisle <davidc@xxxxxxxxx> Date: Wed, 2 Apr 2008 21:08:37 +0100 |
> For some reason I could not get David Carlisle's method to work. perhaps because, depending on how charitable you're feeling, my answer was unduly cryptic, or wrong. The general model is to do what I posted [position() mod 5 = 1] but I failed to observe that your existing selection wasn't a single step foo/bar[position() mod 5 = 1] selects every 5th element child of each foo, whereas you wanted every 5th item in the sequence so that's (foo/bar)[position() mod 5 = 1] but it's probably simpler to use for-each-group anyway, as (because the initial items are mot selected with a simple step) you'd have to use a correspondingly more complicated expression to select the following ones (or did as I posted in 2nd reply) use the compartively more expensive following axis rather than following-sibling. David ________________________________________________________________________ The Numerical Algorithms Group Ltd is a company registered in England and Wales with company number 1249803. The registered office is: Wilkinson House, Jordan Hill Road, Oxford OX2 8DR, United Kingdom. This e-mail has been scanned for all viruses by Star. The service is powered by MessageLabs. ________________________________________________________________________
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