Subject: Re: [xsl] adding hierarchy From: Florent Georges <lists@xxxxxxxxxxxx> Date: Thu, 3 Apr 2008 20:04:08 +0200 (CEST) |
Jim_Albright@xxxxxxxxxxxx wrote: Hi > <xsl:template match="item[following::*[1]=following::list[1]]"> If you want to test if the following element is a 'list', use instead: item[following::*[1][self::list]] > <xsl:element name="item"> This is not an error, but this is usually easier to read when you use literal elements: <item> Regards, --drkm _____________________________________________________________________________ Envoyez avec Yahoo! Mail. Plus de moyens pour rester en contact. http://mail.yahoo.fr
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